Question 4 - Constructing a triangle when 3 sides known (SSS) - Practical Geometry

Last updated at Dec. 16, 2024 by

Ex 10.2, 4 - Construct ABC such that AB = 2.5 cm, BC = 6 cm, AC = 6.5

Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 3
Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 4
Ex 10.2, 4 - Chapter 10 Class 7 Practical Geometry - Part 5

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Transcript

Question 4 Construct ∆ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment AB of length 2.5 cm 2. Taking 6.5 cm as radius, and A as center, draw an arc. 3. Taking 6 cm as radius, and B as center, draw another arc. 4. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle On measuring ∠ B, we see that ∠ B = 90°

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo