Ex 10.2, 3 - Draw PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm

Ex 10.2, 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.2, 3 - Chapter 10 Class 7 Practical Geometry - Part 3
Ex 10.2, 3 - Chapter 10 Class 7 Practical Geometry - Part 4
Ex 10.2, 3 - Chapter 10 Class 7 Practical Geometry - Part 5

Go Ad-free

Transcript

Question 3 Draw ∆PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this? First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment PQ of length 4 cm 2. Taking 4 cm as radius, and P as center, draw an arc. 3. Taking 3.5 cm as radius, and Q as center, draw another arc. 4.Let R be the point where the two arcs intersect Join PR and QR and label the sides Let R be the point where the two arcs intersect Join PR and QR and label the sides Thus, Δ PQR is the required triangle Since two sides are equal ∴ Δ PQR is an sssssssssss Let R be the point where the two arcs intersect Join PR and QR and label the sides Thus, Δ PQR is the required triangle Since two sides are equal ∴ Δ PQR is an sssssssssss

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo