Ex 10.2, 2 - Construct an equilateral triangle of side 5.5 cm

Ex 10.2, 2 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.2, 2 - Chapter 10 Class 7 Practical Geometry - Part 3
Ex 10.2, 2 - Chapter 10 Class 7 Practical Geometry - Part 4
Ex 10.2, 2 - Chapter 10 Class 7 Practical Geometry - Part 5

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Question 2 Construct an equilateral triangle of side 5.5 cm. Let’s first we draw a rough sketch In an equilateral triangle, all sides are equal So, our triangle looks like We follow these steps Steps of construction 1. Draw a line segment AB of length 5.5 cm 2. Taking 5.5 cm as radius, and A as center, draw an arc. 3. Taking 5.5 cm as radius, and B as center, draw another arc. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo