Ex 6.5, 5 - Chapter 6 Class 7 Triangle and its Properties

Last updated at April 16, 2024 by

Ex 6.5, 5 - A tree is broken at a height of 5 m from the ground and

Ex 6.5, 5 - Chapter 6 Class 7 Triangle and its Properties - Part 2

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Ex 6.5, 5 A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree. Given that tree breaks down Let the part after breaking down be AB Distance of its top from base of tree be BC Since Tree is vertical ∠ B = 90° and AB = 5 m BC = 12 m In Δ ABC By Pythagoras Theorem, 〖(𝐴𝐶)〗^2 = 〖(𝐴𝐵)〗^2 + 〖(𝐵𝐶)〗^2 〖(𝐴𝐶)〗^2 = 〖(12)〗^2 + 〖(5)〗^2 〖(𝐴𝐶)〗^2 = 144 + 25 〖(𝐴𝐶)〗^2 = 169 〖(𝐴𝐶)〗^2 = 〖(13)〗^2 Cancelling square AC = 13 m Original height of tree = AB + AC = 5 + 13 = 18 m ∴ Original height of tree is 18 m

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo