Chapter 6 Class 8 Cubes and Cube Roots
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Example 4 - Chapter 6 Class 8 Cubes and Cube Roots

Last updated at April 16, 2024 by

Example 4 - Is 1188 a perfect cube? If not, by which number should it

Example 4 - Chapter 7 Class 8 Cubes and Cube Roots - Part 2

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Example 4 Is 1188 a perfect cube? If not, by which smallest natural number should 1188 be divided so that the quotient is a perfect cube? We see that 1188 = 2 × 2 × 3 × 3 × 3 × 11 Since 2 & 5 does not occur in triplets, ∴ 1188 is not a perfect cube. To make it a perfect cube, We divide by 2 × 2 × 11 = 44 1188/44= (2 × 2 × 3 × 3 × 3 × 11)/44 27 = 3 × 3 × 3 Since all factor occurs in triplets. ∴ 27 is a perfect cube. Thus, the required smallest number is 44.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo