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Example 3 - Chapter 5 Class 8 Squares and Square Roots
Last updated at Dec. 16, 2024 by Teachoo
Chapter 5 Class 8 Squares and Square Roots
Concept wise
- Square numbers
- Properties of square numbers
- Sum of consecutive odd numbers
- Numbers between square numbers
- Pattern Solving
- Finding square of large numbers
-
Pythagorean triplets
- Square root
- Finding Square root through repeated subtraction
- Finding Square root through prime factorisation
- Checking if perfect square by prime factorisation
- Smallest number multiplied to get perfect square
- Smallest number divided to get perfect square
- Smallest square number divisible by numbers
- Finding number of digits in square root (without calculation)
- Finding square root by division method - Integers
- Least number subtracted to get a perfect square
- Least number added to get a perfect square
- Finding square root by division method - Decimals
- Statement Questions
Transcript
Example 3 Find a Pythagorean triplet in which one member is 12. We know 2m, 𝑚^2−1 and 𝑚^2+1 form a Pythagorean triplet. Given, One member of the triplet = 12. Let 2m = 12 2m = 12 m = 12/2 m = 6 Let 𝒎^𝟐−𝟏" = 12" 𝑚^2 = 12 + 1 𝑚^2 = 13 Since, 13 is not a square number, ∴ 𝑚^2−1 ≠ 12 It is not possible. Let 𝒎^𝟐+𝟏 = 12 𝑚^2 = 12 − 1 𝑚^2 = 11 Since, 11 is not a square number, ∴ 𝑚^2+1 ≠ 12 It is not possible. Therefore, m = 6 Finding Triplets for m = 6 1st number = 2m 2nd number = 𝑚^2−1 3rd number = 𝑚^2+1 ∴ The required triplet is 12, 35, 37
