You are here
Ex 5.3, 10 - Chapter 5 Class 8 Squares and Square Roots
Last updated at April 16, 2024 by Teachoo
Chapter 5 Class 8 Squares and Square Roots
Concept wise
- Square numbers
- Properties of square numbers
- Sum of consecutive odd numbers
- Numbers between square numbers
- Pattern Solving
- Finding square of large numbers
- Pythagorean triplets
- Square root
- Finding Square root through repeated subtraction
- Finding Square root through prime factorisation
- Checking if perfect square by prime factorisation
- Smallest number multiplied to get perfect square
- Smallest number divided to get perfect square
-
Smallest square number divisible by numbers
- Finding number of digits in square root (without calculation)
- Finding square root by division method - Integers
- Least number subtracted to get a perfect square
- Least number added to get a perfect square
- Finding square root by division method - Decimals
- Statement Questions
Transcript
Ex 5.3, 10 Find the smallest square number that is divisible by each of the numbers 8, 15 and 20.Smallest square number divisible by 8, 15, 20 = L.C.M of 8, 15, 20 Or Multiple of L.C.M Finding L.C.M of 8, 15, 20 L.C.M of 8, 15, 20 = 2 × 2 × 2 × 3 × 5 = 4 × 6 × 5 = 4 × 30 = 120 Checking if 120 is a perfect square We see that, 120 = 2 × 2 × 2 × 3 × 5 Here, 2, 3 & 5 do not occur in pairs ∴ 120 is not a perfect square So, we multiply by 2, 3 and 5 to make pairs So, our number becomes 120 × 2 × 3 × 5 = 2 × 2 × 2 × 3 × 5 × 2 × 3 × 5 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 Now, it becomes a perfect square. So, required number is 3600
