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Ex 5.1, 5 - Chapter 5 Class 8 Squares and Square Roots
Last updated at Dec. 16, 2024 by Teachoo
Chapter 5 Class 8 Squares and Square Roots
Concept wise
- Square numbers
- Properties of square numbers
- Sum of consecutive odd numbers
- Numbers between square numbers
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Pattern Solving
- Finding square of large numbers
- Pythagorean triplets
- Square root
- Finding Square root through repeated subtraction
- Finding Square root through prime factorisation
- Checking if perfect square by prime factorisation
- Smallest number multiplied to get perfect square
- Smallest number divided to get perfect square
- Smallest square number divisible by numbers
- Finding number of digits in square root (without calculation)
- Finding square root by division method - Integers
- Least number subtracted to get a perfect square
- Least number added to get a perfect square
- Finding square root by division method - Decimals
- Statement Questions
Transcript
Ex 5.1, 5 Observe the following pattern and supply the missing numbers. 11^2 = 1 2 1 〖 101〗^2 = 1 0 2 0 1 〖 10101〗^2 = 102030201 1010101^2 = ........................... 〖"................" 〗^2= 10203040504030201 1012 = 10201 Number of 1s in 101 is = 2 So we write numbers upto 2 & then decrease 1012 = Now, Adding 1 zero between the Digits 1012 = 101012 = 102030201 Number of 1s in 101 is = 3 So we write numbers upto 3 & then decrease 101012 = Now, Adding 1 zero between the Digits 101012 = 10101012 = ………….. Number of 1s in 101 is = 4 So we write numbers upto 4 & then decrease 10101012 = Now, Adding 1 zero between the Digits 10101012 = 〖"................" 〗^2= 10203040504030201 Since number on left is till 5 Number of 1s on left number = 5 and we will add one zero between it The number will be = 10203040504030201
