Example 3 - Playing with Numbers

Last updated at April 16, 2024 by

Example 3 - Find the digits A and B - BA x B3 = 57A - Examples

Example 3 - Chapter 16 Class 8 Playing with Numbers - Part 2
Example 3 - Chapter 16 Class 8 Playing with Numbers - Part 3
Example 3 - Chapter 16 Class 8 Playing with Numbers - Part 4
Example 3 - Chapter 16 Class 8 Playing with Numbers - Part 5

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Transcript

Example 3 Find the digits A & B Here, A × 3 ends with A We put different values of A, and check which ends with A ∴ A can be 0, or 5 Checking for A = 0, B = 9 Putting values Since multiplication is not 570 ∴ A = 0 is not possible Checking for A = 0, B = 9 Putting values Since multiplication is not 570 ∴ A = 0 is not possible For A = 5 Calculating Multiplication Here, (3B + 1) + 5B ends with 7 i.e. 8B + 1 ends with 7 Checking different values of B ∴ B = 2 Checking for A = 5, B = 2 Putting values Hence verified ∴ A = 5 and B = 2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo