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Question 3 - Solving Linear Equations - Making equation simpler and then solving - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at Dec. 16, 2024 by Teachoo
Solving Linear Equations - Making equation simpler and then solving
Chapter 2 Class 8 Linear Equations in One Variable
Concept wise
- Definitions
- Solving Linear Equations - Variables on 1 side
- Solving Linear Equations - Variables on both sides
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Solving Linear Equations - Making equation simpler and then solving
- Forming Linear Equations - Perimeter and Area
- Forming Linear Equations - Fraction - Denominator & Numerator
- Forming Linear Equations - Cost, Sale, Profit
- Forming Linear Equations - Consecutive Numbers
- Forming Linear Equations - Consecutive Multiples
- Forming Linear Equations - Coins and Currency Notes
- Forming Linear Equations - Adding subtracting numbers
- Forming Linear Equations - Two digit number
- Forming Linear Equations - Age
Transcript
Question 3 Solve the following equations. 𝑧/(𝑧 + 15)=4/99z = 4 (z + 15) 9z = 4z + 60 9z − 4z = 60 5z = 60 z = 60/5 z = 12 Check:- L.H.S = 𝑧/(𝑧 + 15) =12/(12 + 15)=12/27 =4/9 = R.H.S ∴ LHS = RHS Hence Verified.
