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Ex 2.2, 6 - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at April 16, 2024 by Teachoo
Solving Linear Equations - Making equation simpler and then solving
Chapter 2 Class 8 Linear Equations in One Variable
Concept wise
- Definitions
- Solving Linear Equations - Variables on 1 side
- Solving Linear Equations - Variables on both sides
-
Solving Linear Equations - Making equation simpler and then solving
- Forming Linear Equations - Perimeter and Area
- Forming Linear Equations - Fraction - Denominator & Numerator
- Forming Linear Equations - Cost, Sale, Profit
- Forming Linear Equations - Consecutive Numbers
- Forming Linear Equations - Consecutive Multiples
- Forming Linear Equations - Coins and Currency Notes
- Forming Linear Equations - Adding subtracting numbers
- Forming Linear Equations - Two digit number
- Forming Linear Equations - Age
Transcript
Ex 2.2, 6 Solve the following linear equations. 𝑚−(𝑚 − 1)/2=1−(𝑚 − 2)/3𝑚−(𝑚 − 1)/2=1−(𝑚 − 2)/3 (2𝑚 − (𝑚 − 1))/2=1− (𝑚 − 2)/3 (𝟐𝒎 − 𝒎 + 𝟏)/𝟐=𝟏− (𝒎 − 𝟐)/𝟑 ( 𝑚 + 1)/2=1−(𝑚 − 2)/3 ( 𝑚 + 1)/2=(3 − (𝑚 − 2))/3 ( 𝑚 + 1)/2=(3 − 𝑚 + 2)/3 ( 𝑚 + 1)/2=(5 − 𝑚)/3 3 (m + 1) = 2 (5 − m) 3m + 3 = 2 (5 − m) 3m + 3 = 10 − 2m 3m + 2m + 3 = 10 5m + 3 = 10 5m + 3 = 10 5m = 10 − 3 5m = 7 m = 𝟕/𝟓 Check:- L.H.S 𝑚−(𝑚 − 1)/2 =7/5−(7/5 − 1)/2 = 7/5− ( (7 − 5)/5 )/2=7/5−2/10 =7/5−1/5=6/5 R.H.S 1−(𝑚 − 2)/3 =1−(7/5 − 2)/3 = 1− ( (7 − 2(5))/5 )/3= 1 – ((7 − 10)/5)/3 = 1 – (−3/5)/3 = 1 + 3/15 =1+1/5=𝟔/𝟓 ∴ LHS = RHS Hence Verified.
