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Question 2 - Forming Linear Equations - Adding subtracting numbers - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at Dec. 16, 2024 by Teachoo
Forming Linear Equations - Adding subtracting numbers
Chapter 2 Class 8 Linear Equations in One Variable
Concept wise
- Definitions
- Solving Linear Equations - Variables on 1 side
- Solving Linear Equations - Variables on both sides
- Solving Linear Equations - Making equation simpler and then solving
- Forming Linear Equations - Perimeter and Area
- Forming Linear Equations - Fraction - Denominator & Numerator
- Forming Linear Equations - Cost, Sale, Profit
- Forming Linear Equations - Consecutive Numbers
- Forming Linear Equations - Consecutive Multiples
- Forming Linear Equations - Coins and Currency Notes
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Forming Linear Equations - Adding subtracting numbers
- Forming Linear Equations - Two digit number
- Forming Linear Equations - Age
Transcript
Question 2 A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers?Let the other number be x Given that, A positive number is 5 times that number ∴ Positive number = 5x Now, 21 added to both numbers, ∴ New other number = x + 21 New positive number = 5x + 21 Given that, One of the new number becomes twice of the other new number 5x + 21 = 2 (x + 21) 5x + 21 = 2x + 42 5x − 2x + 21 = 42 3x + 21 = 42 3x = 42 − 21 3x = 21 x = 21/3 x = 7 ∴ Another number is x = 7 Positive number is 5x = 5 × 7 = 35 Rough Here, First new number = x + 21 Second number = 5x + 21 So, second number is greater Second number will be twice of first ∴ It will be 5x + 21 = 2 (x + 21)
