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Ex 1.3, 7 An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.Now, Total distance elevator has to travel = Initial position − Final position = 10 − (−350) = 10 + 350 = 360 m Now, Elevator descends at rate 6m / min Elevator travels 6 m in = 1 minute Elevator travels 1 m in = 𝟏/𝟔 minute Elevator travels 360 m in = 𝟏/𝟔 × 360 minutes = 60 minutes = 1 hour ∴ It will take the elevator 1 hour to reach −350 m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo