Ex 3.7, 4 - Chapter 3 Class 6 Playing with Numbers
Last updated at Dec. 16, 2024 by Teachoo
Statement questions on LCM
How to check if LCM is to be found or HCF
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Chapter 3 Class 6 Playing with Numbers
Concept wise
- Factors and Multiples
- Perfect number
- Prime and Composite Numbers
- Sum of prime numbers
- Prime numbers from 1 to 100
- Divisibility Tests - Divisibility by 5, 10, 2
- Divisibility Tests - Divisibility by 4, 8
- Divisibility Tests - Divisibility by 3, 6, 9
- Divisibility Tests - Divisibility by 11
- Divisibility Tests - All
- Common Multiples
- Common Factors
- More Divisibility Rules
- Factor Tree
- Prime Factorisation
- Highest Common Factor
- Lowest Common Multiple
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Statement questions on LCM
- Statement questions on HCF
Transcript
Let’s first find smallest number divisible by 6, 8, 12 Smallest number divisible by 6, 8, 12 = LCM of 6, 8, 12 LCM of 6, 8, 12 So LCM = 2 × 2 × 2 × 3 = 24 ∴ 24 is the smallest number divisible by 6, 8, 12 Now, We need to find smallest 3-digit number divisible by 6, 8, 12 Smallest 3 digit number = 100 We divide 100 by 24 So remainder is 4 But we need to find a number where remainder is 0. ∴ Required number = 100 + (24 − 4) = 100 + 20 = 120 So, 120 is the smallest 3 digit number
