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Ex 3.6, 3 - Chapter 3 Class 6 Playing with Numbers
Last updated at April 16, 2024 by Teachoo
Highest Common Factor
Chapter 3 Class 6 Playing with Numbers
Concept wise
- Factors and Multiples
- Perfect number
- Prime and Composite Numbers
- Sum of prime numbers
- Prime numbers from 1 to 100
- Divisibility Tests - Divisibility by 5, 10, 2
- Divisibility Tests - Divisibility by 4, 8
- Divisibility Tests - Divisibility by 3, 6, 9
- Divisibility Tests - Divisibility by 11
- Divisibility Tests - All
- Common Multiples
- Common Factors
- More Divisibility Rules
- Factor Tree
- Prime Factorisation
-
Highest Common Factor
- Lowest Common Multiple
- Statement questions on LCM
- Statement questions on HCF
Transcript
Ex 3.6, 3 HCF of co-prime numbers 4 and 15 was found as follows by factorization : 4 = 2 × 2 and 15 = 3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF? HCF of 4 & 5 We do prime factorisation of both 4 and 5 Thus, 4 = 2 × 2 15 = 3 × 5 Since there are no prime common factors The only common factor will be 1 So, HCF = 1 ∴ HCF will not be 0, but 1.
