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Question 2 - More Divisibility Rules - Chapter 3 Class 6 Playing with Numbers
Last updated at Dec. 16, 2024 by Teachoo
Chapter 3 Class 6 Playing with Numbers
Concept wise
- Factors and Multiples
- Perfect number
- Prime and Composite Numbers
- Sum of prime numbers
- Prime numbers from 1 to 100
- Divisibility Tests - Divisibility by 5, 10, 2
- Divisibility Tests - Divisibility by 4, 8
- Divisibility Tests - Divisibility by 3, 6, 9
- Divisibility Tests - Divisibility by 11
- Divisibility Tests - All
- Common Multiples
- Common Factors
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More Divisibility Rules
- Factor Tree
- Prime Factorisation
- Highest Common Factor
- Lowest Common Multiple
- Statement questions on LCM
- Statement questions on HCF
Transcript
Question 2 Determine if 25110 is divisible by 45. [Hint : 5 and 9 are co-prime numbers. Test the divisibility of the number by 5 and 9].To check if 25110 is divisible by 45, We check if 25110 is divisible by 5 & 9 Checking divisibility by 5 25110 ends with 0 So, it is divisible by 5 Checking divisibility by 9 Sum of digits = 2 + 5 + 1 + 1 + 0 = 9 9 is divisible by 9 So 25110 is also divisible by 9 We know that If a number is divisible by two co-prime numbers, it is divisible their product Since 25110 is divisible by two co-prime numbers 5 & 9 It is divisible by their product 5 × 9 = 45 also. Hence, 25110 is divisible by 45
