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Ex 3.5, 5 - Chapter 3 Class 6 Playing with Numbers
Last updated at Dec. 16, 2024 by Teachoo
Chapter 3 Class 6 Playing with Numbers
Concept wise
- Factors and Multiples
- Perfect number
- Prime and Composite Numbers
- Sum of prime numbers
- Prime numbers from 1 to 100
- Divisibility Tests - Divisibility by 5, 10, 2
- Divisibility Tests - Divisibility by 4, 8
- Divisibility Tests - Divisibility by 3, 6, 9
- Divisibility Tests - Divisibility by 11
- Divisibility Tests - All
- Common Multiples
- Common Factors
- More Divisibility Rules
- Factor Tree
-
Prime Factorisation
- Highest Common Factor
- Lowest Common Multiple
- Statement questions on LCM
- Statement questions on HCF
Transcript
Ex 3.5, 5 Find all the prime factors of 1729 and arrange them in ascending order. Now state the relation, if any; between two consecutive prime factors.To find the factors, we do Prime factorization of 1729 1729 = 7 × 13 × 19 So, factors are 7, 13, 19 Here, difference between two factors is 6 Rough Here, 1729 is not divisible by 2, 3, 5. So, we try with 7 Here, 247 is not divisible by 7 or 11. So, we try with 13. 19 is a prime number So, we divide it by 19 1729 divided by 7 is 247 247 cannot be divided by 7 247 divided by 13 is 19
