The sum of first n terms of an AP is given by S n = 2n 2 + 3n . Find the sixteenth term of the AP.
This is a question of CBSE Sample Paper - Class 10 - 2017/18.
You can download the question paper here https://www.teachoo.com/cbse/sample-papers/
CBSE Class 10 Sample Paper for 2018 Boards
Question 1 Important
Question 2
Question 3
Question 4 Important
Question 5
Question 6 Important
Question 7 Important
Question 8 You are here
Question 9 Important
Question 10
Question 11 Important
Question 12
Question 13 Important
Question 14
Question 15 Important
Question 16 Important
Question 17 Important
Question 18
Question 19 Important
Question 20
Question 21
Question 22 Important
Question 23
Question 24 Important
Question 25
Question 26
Question 27 Important
Question 28 Important
Question 29
Question 30 Important
CBSE Class 10 Sample Paper for 2018 Boards
Last updated at April 16, 2024 by Teachoo
This is a question of CBSE Sample Paper - Class 10 - 2017/18.
You can download the question paper here https://www.teachoo.com/cbse/sample-papers/
Question 8 The sum of first n terms of an AP is given by Sn = 2n2 + 3n . Find the sixteenth term of the AP. Given Sn = 2n2 + 3n Taking n = 1 S1 = 2 12 + 3 1 = 2 + 3 = 5 So, Sum of first term of AP is 5 But sum of first term will be the first term So, First term = a = 5 Taking n = 2 in Sn S1 = 2 22 + 3 2 S2 = 2 4 + 6 S2 = 8 + 6 S2 = 14 Sum of first 2 terms is 14 Finding 2nd term Sum of first 2 terms is 14 First term + Second term = 14 5 + a2 = 14 a2 = 14 5 a2 = 9 Hence in AP , First term = a = 3 Common difference = d = Second term First term = 9 5 = 4 We need to find 16th term We know that an = a + (n 1) d a16 = a + (16 1) d = a + 15d = 5 + 15 4 = 5 + 60 = 65