Class 10
Solutions of Sample Papers for Class 10 Boards

Question 5 - CBSE Class 10 Sample Paper for 2018 Boards - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 16, 2024 by

In given figure, ST ∥ RQ, PS = 3 cm and SR = 4 cm. Find the ratio of the area of ∆PST to the area of ∆PRQ.

This is a question of CBSE Sample Paper - Class 10 - 2017/18.

You can download the question paper here  https://www.teachoo.com/cbse/sample-papers/

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Question 5 - CBSE Class 10 Sample Paper for 2018 Boards - Part 2

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Transcript

Question 5 In given figure, ST RQ, PS = 3 cm and SR = 4 cm. Find the ratio of the area of PST to the area of PRQ. Given: ABC ST II RQ PS = 3 cm, SR = 4cm To find : ( )/( ) Proof: In PRQ & PST, QPR = TPS PRQ = PST PRQ ~ PST Now, we know that in similar triangles, Ratio of area of triangle is equal to ratio of square of corresponding sides ( )/( )=( / )^2 ( )/( )=( /( + ))^2 ( )/( )=(3/(3 + 4))^2 ( )/( )=(3/7)^2 ( )/( )=9/49 Required Ratio = 9 : 49 (Putting PS = 3 cm, SR = 4 cm)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo