Suppose angle of elevation from point A to the top of the tower is 45°. And distance from point A to the bottom of tower is 10m.
What is the height of the tower?
Let building be BC
So, ∠ BAC = 45°
and AC = 10 m
Now, we need to find height of tower i.e. BC
And we are given base 10 m.
So, we can use tan
As
tan A = Side opposite to angle A / Side adjacent to angle A
tan 45° = BC / AC
1 = BC/ 10
1 × 10 = BC
10 = BC
BC = 10 m
∴ Height of tower is 10 m