Example 26 (Supplementary NCERT) - Chapter 10 Class 12 Vector Algebra

Last updated at Dec. 16, 2024 by Teachoo

Example 26 (Supplementary NCERT) - Find a.(b x c), if a = 2i + j + 3k

Example 26 (Supplementary NCERT) - Chapter 10 Class 12 Vector Algebra - Part 2

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Example 26 (Supplementary NCERT) Find 𝑎 ⃗.(𝑏 ⃗ × 𝑐 ⃗), if 𝑎 ⃗ = 2𝑖 ̂ + 𝑗 ̂ + 3𝑘 ̂ , 𝑏 ⃗ = –𝑖 ̂ + 2𝑗 ̂ + 𝑘 ̂ , 𝑐 ⃗ = 3𝑖 ̂ + 𝑗 ̂ + 2𝑘 ̂Given, 𝒂 ⃗ = 2𝑖 ̂ + 𝑗 ̂ + 3𝑘 ̂ , 𝒃 ⃗ = –𝑖 ̂ + 2𝑗 ̂ + 𝑘 ̂ , 𝒄 ⃗ = 3𝑖 ̂ + 𝑗 ̂ + 2𝑘 ̂ 𝒂 ⃗.(𝒃 ⃗ × 𝒄 ⃗) = [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] = |■8(𝟐&𝟏&𝟑@−𝟏&𝟐&𝟏@𝟑&𝟏&𝟐)| = 2[(2×2)−(1×1) ] − 1[(−1×2)−(3×1) ] + 3[(−1×1)−(3×2)] = 2 [4−1]−1(−2−3)+3[−1−6] = 2(3) – 1(–5) + 3(–7) = 6 + 5 – 21 = 11 – 21 = – 10 ∴ 𝑎 ⃗.(𝑏 ⃗ × 𝑐 ⃗) = –10

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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