Question 5 - Chapter 11 Class 9 Constructions (Important Question)

Last updated at Dec. 16, 2024 by

Ex 11.2, 5 - Construct a right triangle whose base is 12cm and sum

Ex 11.2, 5 - Chapter 11 Class 9 Constructions - Part 2
Ex 11.2, 5 - Chapter 11 Class 9 Constructions - Part 3
Ex 11.2, 5 - Chapter 11 Class 9 Constructions - Part 4

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Question 5 Construct a Right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. Let Δ ABC be the right angled triangle where BC = 12 cm, ∠ B = 90° and AC + AB = 18 cm Steps of Construction: Draw base BC of length 12 cm 2. Now, let’s draw ∠ B = 90° Let the ray be BX Check Ex 11.1, 1 on how to construct 90° 3. Open the compass to length AB + AC = 18 cm. From point B as center, cut an arc on ray BX. Let the arc intersect BX at D 4. Join CD Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo