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Question 5 - Constructing Triangle - Given base, angle and sum of other 2 sides - Constructions
Last updated at April 16, 2024 by Teachoo
Constructing Triangle - Given base, angle and sum of other 2 sides
Constructions
Concept wise
- Constructing bisector of angle and perpendicular bisector
- Constructing angles - 60, 90, 45, 30 and others
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Constructing Triangle - Given base, angle and sum of other 2 sides
- Constructing Triangle - Given base, angle and difference of sides
- Constructing Triangle - Given sum of 3 sides and 2 base angles
Transcript
Question 5 Construct a Right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. Let Δ ABC be the right angled triangle where BC = 12 cm, ∠ B = 90° and AC + AB = 18 cm Steps of Construction: Draw base BC of length 12 cm 2. Now, let’s draw ∠ B = 90° Let the ray be BX Check Ex 11.1, 1 on how to construct 90° 3. Open the compass to length AB + AC = 18 cm. From point B as center, cut an arc on ray BX. Let the arc intersect BX at D 4. Join CD Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle
