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Question 3 - Constructing Triangle - Given base, angle and difference of sides - Constructions
Last updated at April 16, 2024 by Teachoo
Constructing Triangle - Given base, angle and difference of sides
Constructions
Concept wise
- Constructing bisector of angle and perpendicular bisector
- Constructing angles - 60, 90, 45, 30 and others
- Constructing Triangle - Given base, angle and sum of other 2 sides
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Constructing Triangle - Given base, angle and difference of sides
- Constructing Triangle - Given sum of 3 sides and 2 base angles
Transcript
Question 3 Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm. Steps of Construction: Draw base QR of length 6 cm 2. Now, let’s draw ∠ Q = 60° Let the ray be QX Open the compass to length PR – PQ = 2 cm. From point Q as center, cut an arc on ray QX. (opposite side of QR). Let the arc intersect QX at D 4. Join RD Note: Since PR – PQ = 2 cm, (PQ – PR) is negative So, QD will be below line QR Now, we will draw perpendicular bisector of RD 6. Mark point P where perpendicular bisector intersects RD Join PR ∴ Δ PQR is the required triangle
