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Ex 13.1, 3 Find the mean deviation about the median for the data. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 Arranging data in ascending order, 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Here, n = number of observations = 12 (even) Since n is even Median = đ‘›īˇŽ2īˇ¯īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗđ‘Žđ‘Ąđ‘–đ‘œđ‘› + đ‘›īˇŽ2 + 1īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗđ‘Žđ‘Ąđ‘–đ‘œđ‘›īˇŽ2 M = 12īˇŽ2īˇ¯īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗđ‘Žđ‘Ąđ‘–đ‘œđ‘› + 12īˇŽ2 + 1īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗđ‘Žđ‘Ąđ‘–đ‘œđ‘›īˇŽ2 M = 6īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗđ‘Žđ‘Ąđ‘–đ‘œđ‘› + 7īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗđ‘Žđ‘Ąđ‘–đ‘œđ‘›īˇŽ2 M = 13 + 14īˇŽ2 = 27īˇŽ2 = 13.5 Thus, for 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Median = 13.5 Mean deviation about median = īˇŽīˇŽ đ‘Ĩ𝑖 −Mīˇ¯īˇ¯īˇŽ12 = 10 − 13.5 + 11 − 13.5 + 11 − 13.5 + 12 − 13.5 + 13 − 13.5+ 13 − 13.5īˇ¯īˇŽ+ 14 − 13.5 + 16 − 13.5 + 16 − 13.5 + 17 − 13.5 + 17 − 13.5+ 18 − 13.5īˇ¯īˇ¯īˇ¯īˇŽ12 = −3.5 + −2.5 + −2.5 + −1.5 + −0.5 + −0.5īˇ¯īˇŽ+ 0.5 + 2.5 + 2.5+ 3.5 + 3.5 + 4.5 īˇ¯īˇ¯īˇŽ12 = 3.5 + 2.5 + 2.5 + 1.5 + 0.5 + 0.5 + 0.5 + 2.5 + 2.5 + 3.5 + 3.5 + 4.5īˇŽ12 = 28īˇŽ12 = 2.33

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo