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Ex 13.1, 2 Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44 Mean of the given data = (𝑆𝑢𝑚 𝑜𝑓 𝑎𝑙𝑙 𝑡𝑒𝑟𝑚𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑡𝑒𝑟𝑚𝑠) 𝑥 ̅ = (38 + 70 + 48 + 40 + 42 + 55 + 63 + 46 + 54 + 44)/(10 ) = 500/10 = 50 38 38 – 50 = –12 70 70 – 50 = 20 48 48 – 50 = –2 40 40 – 50 = –10 42 42 – 50 = –8 55 63 46 54 44 Mean deviation about mean = ( ∑128▒|𝑥𝑖 − 𝑥 ̅ | )/10 = 84/10 = 8.4

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo