Ex 2.2, 2 - Chapter 2 Class 12 Inverse Trigonometric Functions

Last updated at Dec. 16, 2024 by

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Ex 2.2, 2 3cos−1 𝑥 = cos−1 (4𝑥^3− 3𝑥 ), 𝑥∈ [1/2,1] Solving R.H.S cos^(−1) (4𝑥^3− 3𝑥 ) Putting x = cos 𝜃 = cos^(−1) (4 〖"cos" 〗^𝟑𝜃 − 3cos 𝜃) = cos^(−1) (cos 3𝜃) = 3𝜃 = 3 cos^(−1) x = L.H.S Hence, proved.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo