Ex 2.2,1 - Chapter 2 Class 12 Inverse Trigonometric Functions
Last updated at Dec. 16, 2024 by Teachoo
Formulae based
Inverse Trigonometry Formulas
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Transcript
Ex 2.2, 1 3sin-1 𝑥 = sin-1 (3𝑥 − 4𝑥^3), 𝑥∈ [−1/2,1/2] Solving R.H.S sin^(−1) (3𝑥 − 4𝑥^3) Putting x = sin 𝜃 = sin^(−1) (3 sin 𝜃 − 4 〖"sin" 〗^3𝜃) = sin^(−1) (sin 3𝜃 ) = 3𝜃 = 3 〖𝒔𝒊𝒏〗^(−𝟏) x = L.H.S Hence, proved.
