Ex 7.2, 26 - Integrate cos root(x) / root x - Teachoo - Ex 7.2

Ex 7.2, 26 - Chapter 7 Class 12 Integrals - Part 2

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Ex 7.2, 26 Integrate the function cosโกโˆš๐‘ฅ/โˆš๐‘ฅ Let โˆš๐‘ฅ=๐‘ก Differentiating both sides ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ (1/2) ๐‘ฅ^(1/2 โˆ’ 1)= ๐‘‘๐‘ก/๐‘‘๐‘ฅ 1/2. ๐‘ฅ^(โˆ’ 1/2)= ๐‘‘๐‘ก/๐‘‘๐‘ฅ 1/(2โˆš๐‘ฅ) = ๐‘‘๐‘ก/๐‘‘๐‘ฅ ๐‘‘๐‘ฅ =2โˆš๐‘ฅ . ๐‘‘๐‘ก ๐‘‘๐‘ฅ =2๐‘ก . ๐‘‘๐‘ก Integrating the function โˆซ1โ–’ใ€–" " cosโกโˆš๐‘ฅ/โˆš๐‘ฅ " " ใ€—. ๐‘‘๐‘ฅ Putting โˆš๐‘ฅ=๐‘ก & ๐‘‘๐‘ฅ=2๐‘ก . ๐‘‘๐‘ก = โˆซ1โ–’ใ€–" " cosโก๐‘ก/๐‘กใ€—. 2๐‘ก . ๐‘‘๐‘ก = โˆซ1โ–’ใ€–" " 2 cosโก๐‘ก ใ€—. ๐‘‘๐‘ก = 2โˆซ1โ–’cosโก๐‘ก . ๐‘‘๐‘ก = 2 sinโก๐‘ก+๐ถ = ๐Ÿ ๐’”๐’Š๐’โกโˆš๐’™+๐‘ช (๐‘ˆ๐‘ ๐‘–๐‘›๐‘” ๐‘ก=โˆš๐‘ฅ)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo