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Ex 7.7, 5 - Chapter 7 Class 12 Integrals
Last updated at Dec. 16, 2024 by Teachoo
Integration by specific formulaes - Formula 8
Chapter 7 Class 12 Integrals
Concept wise
- Using Formulaes
- Using Trignometric Formulaes
- Integration by substitution - x^n
- Integration by substitution - lnx
- Integration by substitution - e^x
- Integration by substitution - Trignometric - Normal
- Integration by substitution - Trignometric - Inverse
- Integration using trigo identities - sin^2,cos^2 etc formulae
- Integration using trigo identities - a-b formulae
- Integration using trigo identities - 2x formulae
- Integration using trigo identities - 3x formulae
- Integration using trigo identities - CD and CD inv formulae
- Integration using trigo identities - Inv Trigo formulae
- Integration by parts
- Integration by parts - e^x integration
- Integration by specific formulaes - Formula 1
- Integration by specific formulaes - Formula 2
- Integration by specific formulaes - Formula 3
- Integration by specific formulaes - Formula 4
- Integration by specific formulaes - Formula 5
- Integration by specific formulaes - Formula 6
- Integration by specific formulaes - Formula 7
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Integration by specific formulaes - Formula 8
- Integration by specific formulaes - Method 9
- Integration by specific formulaes - Method 10
- Integration by partial fraction - Type 1
- Integration by partial fraction - Type 2
- Integration by partial fraction - Type 3
- Integration by partial fraction - Type 4
- Integration by partial fraction - Type 5
- Definite Integral as a limit of a sum
- Definite Integration - By Formulae
- Definite Integration - By Partial Fraction
- Definite Integration - By e formula
- Definite Integration - By Substitution
- Definite Integration by properties - P2
- Definite Integration by properties - P3
- Definite Integration by properties - P4
- Definite Integration by properties - P6
- Definite Integration by properties - P7
Transcript
Ex7.7, 5 (1 4 2) 1 (1 4 ^2 ) . = 1 (1 (4 + ^2 ) ) . = 1 (1 ( ^2+4 ) ) . = 1 (1 ( ^2+2.2. ) ) = 1 (1 [ ^2+2.2. +(2)^2 (2)^2 ] ) = 1 (1 [( +2)^2 4] ) . = 1 (1 ( +2)^2+4 ) = 1 (5 ( +2)^2 ) = 1 (( 5)^2 ( +2)^2 ) = (( + 2))/2 (( 5)^2 ( +2)^2 )+( 5)^2/2 sin^( 1) (( + 2)/ 5)+ = (( + 2))/2 (5 ( ^2+4 +4))+ 5/2 sin ^( 1) (( + 2)/ 5)+ = (( + 2))/2 (5 ^2 4 4)+5/2 sin ^( 1) (( + 2)/ 5)+ = / ^( ) (( + )/ )+(( + ))/ ( ^ )+
