Ex 7.8, 7 - Chapter 7 Class 12 Integrals
Last updated at Dec. 16, 2024 by Teachoo
Definite Integration - By Formulae
Ex 7.8, 1
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Chapter 7 Class 12 Integrals
Concept wise
- Using Formulaes
- Using Trignometric Formulaes
- Integration by substitution - x^n
- Integration by substitution - lnx
- Integration by substitution - e^x
- Integration by substitution - Trignometric - Normal
- Integration by substitution - Trignometric - Inverse
- Integration using trigo identities - sin^2,cos^2 etc formulae
- Integration using trigo identities - a-b formulae
- Integration using trigo identities - 2x formulae
- Integration using trigo identities - 3x formulae
- Integration using trigo identities - CD and CD inv formulae
- Integration using trigo identities - Inv Trigo formulae
- Integration by parts
- Integration by parts - e^x integration
- Integration by specific formulaes - Formula 1
- Integration by specific formulaes - Formula 2
- Integration by specific formulaes - Formula 3
- Integration by specific formulaes - Formula 4
- Integration by specific formulaes - Formula 5
- Integration by specific formulaes - Formula 6
- Integration by specific formulaes - Formula 7
- Integration by specific formulaes - Formula 8
- Integration by specific formulaes - Method 9
- Integration by specific formulaes - Method 10
- Integration by partial fraction - Type 1
- Integration by partial fraction - Type 2
- Integration by partial fraction - Type 3
- Integration by partial fraction - Type 4
- Integration by partial fraction - Type 5
- Definite Integral as a limit of a sum
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Definite Integration - By Formulae
- Definite Integration - By Partial Fraction
- Definite Integration - By e formula
- Definite Integration - By Substitution
- Definite Integration by properties - P2
- Definite Integration by properties - P3
- Definite Integration by properties - P4
- Definite Integration by properties - P6
- Definite Integration by properties - P7
Transcript
Ex 7.8, 7 β«_0^(π/4)βγπ‘ππ π₯γβ‘ππ₯ Step 1 :- F(π₯)=β«1βγtanβ‘π₯ ππ₯γ =πππ|π ππ π₯| Hence F(π₯)=πππ|π ππ π₯| Step 2 :- β«_0^(π/4)βtanβ‘γπ₯ ππ₯=πΉ(π/4)βπΉ(0)γ =πππ|π ππ (π/4)|βπππ|π ππ(0)| =πππ|β2|βπππ|1| =logβ‘β2β0 =logβ‘β2 = logβ‘γ2^(1/2) γ =π/π πππβ‘π
