Misc 12 - Chapter 7 Class 12 Integrals

Last updated at April 16, 2024 by

Integ p1.jpg

Integ p2.jpg
 

Go Ad-free

Transcript

Misc 12 Integrate the function 3 1 8 3 1 8 = 3 1 4 2 Put 4 = Differentiating w.r.t. 4 3 = d = 4 3 Therefore, 3 1 4 2 = 3 1 2 4 3 = 1 4 1 2 = 1 4 sin 1 + Putting = 4 = +

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo