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Question 3 (Supplementary NCERT) Important
Last updated at April 16, 2024 by Teachoo
Example 8 Find the following integrals: (i) β«1βππ₯/(π₯^2 β16) β«1βππ₯/(π₯^2 β16) = β«1βππ₯/(π₯^2 βγ 4γ^2 ) =1/(2 Γ 4) πππ|(π₯ β 4)/(π₯ + 4)|+πΆ =π/π πππ|(π β π)/(π + π)|+πͺ Using β«1βγππ₯/(π₯^2 β π^2 )=1/2π πππ|(π₯ β π)/(π₯ + π)|+πΆγ Replacing π=4