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Ex 7.1, 21 (MCQ) - Chapter 7 Class 12 Integrals
Last updated at April 16, 2024 by Teachoo
Chapter 7 Class 12 Integrals
Concept wise
-
Using Formulaes
- Using Trignometric Formulaes
- Integration by substitution - x^n
- Integration by substitution - lnx
- Integration by substitution - e^x
- Integration by substitution - Trignometric - Normal
- Integration by substitution - Trignometric - Inverse
- Integration using trigo identities - sin^2,cos^2 etc formulae
- Integration using trigo identities - a-b formulae
- Integration using trigo identities - 2x formulae
- Integration using trigo identities - 3x formulae
- Integration using trigo identities - CD and CD inv formulae
- Integration using trigo identities - Inv Trigo formulae
- Integration by parts
- Integration by parts - e^x integration
- Integration by specific formulaes - Formula 1
- Integration by specific formulaes - Formula 2
- Integration by specific formulaes - Formula 3
- Integration by specific formulaes - Formula 4
- Integration by specific formulaes - Formula 5
- Integration by specific formulaes - Formula 6
- Integration by specific formulaes - Formula 7
- Integration by specific formulaes - Formula 8
- Integration by specific formulaes - Method 9
- Integration by specific formulaes - Method 10
- Integration by partial fraction - Type 1
- Integration by partial fraction - Type 2
- Integration by partial fraction - Type 3
- Integration by partial fraction - Type 4
- Integration by partial fraction - Type 5
- Definite Integral as a limit of a sum
- Definite Integration - By Formulae
- Definite Integration - By Partial Fraction
- Definite Integration - By e formula
- Definite Integration - By Substitution
- Definite Integration by properties - P2
- Definite Integration by properties - P3
- Definite Integration by properties - P4
- Definite Integration by properties - P6
- Definite Integration by properties - P7
Transcript
Ex 7.1, 21 The anti derivative of 𝑥+ 1 𝑥 equals (A) 13 x 13 + 2x 12 + C (B) 23 x 23 + 12 x2 + C (c) 23 x 32 +2x 12 + C (D) 23 x 32 + 12 x 12 + C 𝑥+ 1 𝑥𝑑𝑥 = 𝑥 12+ 1 𝑥 12𝑑𝑥 = 𝑥 12+ 𝑥 −12𝑑𝑥 = 𝑥 12𝑑𝑥+ 𝑥 −12𝑑𝑥 = 𝑥 12 + 1 12 + 1 + 𝑥 −12 + 1 −12 + 1 + 𝐶 = 𝑥 32 32 + 𝑥 12 12 + 𝐶 = 23 𝑥 32 +2 𝑥 12+ 𝐶 ∴ Option (C) is correct .
