Ex 9.3, 2 - Chapter 9 Class 12 Differential Equations

Last updated at April 16, 2024 by Teachoo

Next: Misc 4 → Go Ad-free

Transcript

Ex 9.3, 2 For each of the differential equations in Exercises 1 to 10, find the general solution : 𝑑𝑦/𝑑𝑥=√(4−𝑦^2 ) (−2<𝑦<2) 𝑑𝑦/𝑑𝑥 = √(4−𝑦2) 𝑑𝑦/√(4 − 𝑦^2 ) = dx. 𝒅𝒚/√(𝟐^𝟐 − 𝒚^𝟐 ) = dx Integrating both sides ∫1▒〖𝑑𝑦/√(2^2 − 𝑦^2 )=∫1▒𝑑𝑥〗 We know that ∫1▒〖𝑑𝑥/√(𝑎^2−𝑥^2 )=sin^(−1)⁡〖𝑥/𝑎〗〗 Putting 𝑎 = 2, x = y 〖𝒔𝒊𝒏〗^(−𝟏)⁡〖𝒚/𝟐〗 = x + c 𝑦/2 = sin(x + c) y = 2 sin(x + c) ∴ y = 2 sin (x + c) is the general solution

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

Class 6

Class 7

Class 8

Class 9

Class 10

Class 11

Class 12

Courses

Interesting

Popular