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Misc 13 The general solution of the differential equation (𝑦 𝑑π‘₯βˆ’π‘₯ 𝑑𝑦)/𝑦=0 is (A) π‘₯𝑦=𝐢 (B) π‘₯=𝐢𝑦^2 (C) 𝑦=𝐢π‘₯ (D) 𝑦=𝐢π‘₯^2(𝑦 𝑑π‘₯ βˆ’ π‘₯ 𝑑𝑦)/𝑦=0 ( 𝑦 𝑑π‘₯)/π‘¦βˆ’ ( π‘₯ 𝑑𝑦)/𝑦=0 dx = (π‘₯ 𝑑π‘₯)/𝑦 𝒅𝒙/𝒙 = π’…π’š/π’š Integrating both sides. ∫1β–’γ€–(𝑑π‘₯ )/π‘₯=(𝑑𝑦 )/(𝑦 )γ€— log x = log y + log c1 log x βˆ’ log y = log c1 log ((π‘₯ )/𝑦) = log c1 (𝒙 )/π’š = c1 y = π‘₯/𝑐_1 y = cx So, the correct answer is (c)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo