
Variable separation - Equation given
Variable separation - Equation given
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Misc 13 The general solution of the differential equation (π¦ ππ₯βπ₯ ππ¦)/π¦=0 is (A) π₯π¦=πΆ (B) π₯=πΆπ¦^2 (C) π¦=πΆπ₯ (D) π¦=πΆπ₯^2(π¦ ππ₯ β π₯ ππ¦)/π¦=0 ( π¦ ππ₯)/π¦β ( π₯ ππ¦)/π¦=0 dx = (π₯ ππ₯)/π¦ π π/π = π π/π Integrating both sides. β«1βγ(ππ₯ )/π₯=(ππ¦ )/(π¦ )γ log x = log y + log c1 log x β log y = log c1 log ((π₯ )/π¦) = log c1 (π )/π = c1 y = π₯/π_1 y = cx So, the correct answer is (c)