Question 3 - Formation of Differntial equation when general solution given - Chapter 9 Class 12 Differential Equations
Last updated at Dec. 16, 2024 by Teachoo
Formation of Differntial equation when general solution given
Formation of Differntial equation when general solution given
Last updated at Dec. 16, 2024 by Teachoo
Question 3 Form the differential equation representing the family of ellipses having foci on 𝑥−𝑎𝑥𝑖𝑠 is center at the origin. Ellipse whose foci is on x-axis & center at origin is 𝑥^2/𝑎^2 +𝑦^2/𝑏^2 =1 Differentiating both sides w.r.t. 𝑥 𝑑/𝑑𝑥 [𝑥^2/𝑎^2 +𝑦^2/𝑏^2 ]=𝑑(1)/𝑑𝑥 1/𝑎^2 ×(〖𝑑(𝑥〗^2))/𝑑𝑥+1/𝑏^2 ×(〖𝑑(𝑦〗^2))/𝑑𝑥=0 Since it has two variables, we will differentiate twice 𝑥^2/𝑎^2 +𝑦^2/𝑏^2 =1 1/𝑎^2 ×2𝑥+1/𝑏^2 ×(2𝑦 . 𝑑𝑦/𝑑𝑥)=0 2𝑥/𝑎^2 +2𝑦/𝑏^2 𝑑𝑦/𝑑𝑥=0 2𝑦/𝑏^2 𝑑𝑦/𝑑𝑥=(−2𝑥)/〖 𝑎〗^2 𝑦/𝑏^2 𝑑𝑦/𝑑𝑥=(−𝑥)/〖 𝑎〗^2 𝑦/𝑥 𝑑𝑦/𝑑𝑥= (−𝑏^2)/〖 𝑎〗^2 𝑦/𝑥 𝑦^′= (−𝑏^2)/〖 𝑎〗^2 Again differentiating both sides 𝑑(𝑦/𝑥)/𝑑𝑥. 𝑦^′+𝑦/𝑥 (𝑑(𝑦^′))/𝑑𝑥=𝑑/𝑑𝑥 ((− 𝑏^2)/( 𝑎^2 )) [𝑑𝑦/𝑑𝑥 . 𝑥 − 𝑦 .𝑑𝑥/𝑑𝑥]/𝑥^2 𝑦^′ +𝑦/𝑥 ×𝑦′′=0 [𝑦^′ 𝑥 − 𝑦]/𝑥^2 𝑦^′ +𝑦/𝑥×𝑦′′=0 Multiplying x2 both sides 𝑥^2×[𝑦^′ 𝑥 − 𝑦]/𝑥^2 𝑦^′ +𝑥^2×𝑦/𝑥×𝑦′′=𝑥^2×0 [𝑦^′ 𝑥−𝑦] 𝑦^′+𝑥𝑦𝑦^′′=0 〖〖𝑥𝑦〗^′〗^2−𝑦𝑦^′+𝑥𝑦𝑦^′′=0 𝑥𝑦𝑦^′′+〖〖𝑥𝑦〗^′〗^2−𝑦𝑦^′=0 𝒙𝒚 (𝒅^𝟐 𝒚)/(𝒅𝒙^𝟐 ) +𝒙(𝒅𝒚/𝒅𝒙)^𝟐−𝒚 𝒅𝒚/𝒅𝒙=𝟎 is the required differential equation