Slide15.JPG

Go Ad-free

Transcript

Example 9 Solve – 8 ≤ 5x – 3 < 7. –8 ≤ 5x – 3 < 7 Adding 3 all sides (Eliminating -3) – 8 + 3 ≤ 5x – 3 + 3 < 7 + 3 –5 ≤ 5x < 10 Dividing 5 all sides (Eliminating 5) (−5)/5 ≤ 5𝑥/5 < 10/5 –1 ≤ x < 2 Thus, x is a real number which is less than 2 and greater than or equal to –1 Hence, x ∈ [–1, 2) is the solution

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo