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Ex 5.1, 15 - Chapter 5 Class 11 Linear Inequalities
Last updated at Dec. 16, 2024 by Teachoo
Solving inequality (one side)
Transcript
Ex 5.1, 15 Solve the given inequality for real x: 𝑥4 < (5𝑥 − 2)3 −(7𝑥 − 3)5 𝑥4 < (5𝑥 − 2)3 −(7𝑥 − 3)5 𝑥4 < 55𝑥 − 2 −3 (7𝑥 − 3)3(5) 𝑥4 < 25𝑥 −10 − 21𝑥 + 915 𝑥4 < 25𝑥 − 21𝑥 + 9 −1015 𝑥4 < 4𝑥 − 115 15x < 4 (4x – 1) 15x < 16x – 4 15x – 16x < − 4 –x < −4 Since x is negative, we multiply both sides by -1 & change the signs (– 1) × (–x) > (– 1) × (−4) x > 4 Hence, x is a real number which is greater than 4 Hence, x ∈ (4, is the solution
