Ex 5.1, 12 - Chapter 5 Class 11 Linear Inequalities

Last updated at Dec. 16, 2024 by

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Ex 5.1, 12 Solve the given inequality for real x: 1 2 3 5 +4 1 3 (x 6) 1 2 3 5 +4 1 3 (x 6) 3 3 5 +4 2 (x 6) 3 3 5 + 3 4 2x 2 6 9 5 + 12 2x 12 9 5 2x 12 12 9 5(2 ) 5 24 9 10 5 24 5 24 24 5 120 Since x is negative, we multiply both sides by -1 & change the signs ( 1) ( x) ( 1) ( 120) x 120 Hence, x is a real number which is less than or equal to 120 Hence, x ( 120] is the solution

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo