Ex 5.1, 3 - Chapter 5 Class 11 Linear Inequalities

Last updated at April 16, 2024 by

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Ex 5.1, 3 Solve 5x 3 < 7, when x is an integer 5x 3 < 7 5x < 7 + 3 5x < 10 x < 10 5 x < 2 Since x is an integer ( ,-3,-2,-1,0,1,2,3 .) We need to find values of x which is less than 2 i.e. x can be -3,-2,-1,0,1 = { 3, 2, 1, 0, 1} (ii) x is a real number Now, x < 2 Since x is a real number which is less than 2 Thus x ( 2).

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo