Question 10 - Examples - Chapter 6 Class 12 Application of Derivatives

Last updated at Dec. 16, 2024 by

Example 23 - Find approximate value of f(3.02), f(x)=3x2+5x+3

Example 23 - Chapter 6 Class 12 Application of Derivatives - Part 2

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Question 10 Find the approximate value of f (3.02), where f (x) = 3x2 + 5x + 3.Given f(x) = 3x2 + 5x + 3 where x = 3 and ∆𝑥=0.02 Finding f’(x) f’(x) = 6x + 5 Now, △y = f’(x) ∆𝒙 = (6x + 5) 0.02 Putting x = 3 = (6 × 3 + 5) 0.02 = 23 × 0.02 = 0.46 Now, f(x + ∆𝒙) = f(x) + ∆𝒚 f(3.02) = f(3) + 0.46 = (3 × 32 + 5 × 3 + 3) + 0.46 = (27 + 15 + 3) + 0.46 = 45 + 0.46 = 45.46 Hence, approximate value of f(3.02) is 45.46

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo