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Question 10 - Finding approximate value of function - Chapter 6 Class 12 Application of Derivatives
Last updated at April 16, 2024 by Teachoo
Finding approximate value of function
Chapter 6 Class 12 Application of Derivatives
Concept wise
- Finding rate of change
- To show increasing/decreasing in whole domain
- To show increasing/decreasing in intervals
- Find intervals of increasing/decreasing
- Finding slope of tangent/normal
- Finding point when tangent is parallel/ perpendicular
- Finding equation of tangent/normal when point and curve is given
- Finding equation of tangent/normal when slope and curve are given
- Finding approximate value of numbers
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Finding approximate value of function
- Finding approximate value- Statement questions
- Finding minimum and maximum values from graph
- Local maxima and minima
- Minima/ maxima (statement questions) - Number questions
- Minima/ maxima (statement questions) - Geometry questions
- Absolute minima/maxima
Transcript
Question 10 Find the approximate value of f (3.02), where f (x) = 3x2 + 5x + 3.Given f(x) = 3x2 + 5x + 3 where x = 3 and âđĽ=0.02 Finding fâ(x) fâ(x) = 6x + 5 Now, âły = fâ(x) âđ = (6x + 5) 0.02 Putting x = 3 = (6 Ă 3 + 5) 0.02 = 23 Ă 0.02 = 0.46 Now, f(x + âđ) = f(x) + âđ f(3.02) = f(3) + 0.46 = (3 Ă 32 + 5 Ă 3 + 3) + 0.46 = (27 + 15 + 3) + 0.46 = 45 + 0.46 = 45.46 Hence, approximate value of f(3.02) is 45.46
