Question 4 - Finding slope of tangent/normal - Chapter 6 Class 12 Application of Derivatives

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Ex 6.3, 4 - Find slope of tangent at y = x3 - 3x + 2 at x = 3

Ex 6.3,4 - Chapter 6 Class 12 Application of Derivatives - Part 2

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Question 4 Find the slope of the tangent to the curve 𝑦=π‘₯^3βˆ’3π‘₯+2 at the point whose π‘₯βˆ’coordinate is 3 𝑦=π‘₯^3βˆ’3π‘₯+2 We know that slope of tangent =𝑑𝑦/𝑑π‘₯ 𝑑𝑦/𝑑π‘₯=3π‘₯^2βˆ’3 Since π‘₯βˆ’coordinate is 3 Putting π‘₯=3 in (1) 〖𝑑𝑦/𝑑π‘₯β”‚γ€—_(π‘₯ = 3)=3(3)^2βˆ’3 =3 Γ—9βˆ’3 =27βˆ’3 =24 Hence slope of tangent is 24

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