Ex 6.1, 6 - Radius of a circle is increasing at rate of 0.7 cm/s

Ex 6.1,6 - Chapter 6 Class 12 Application of Derivatives - Part 2
Ex 6.1,6 - Chapter 6 Class 12 Application of Derivatives - Part 3

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Ex 6.1, 6 The radius of a circle is increasing at the rate of 0.7 cm/s. What is the rate of increase of its circumference? Let r be the radius of circle & C be the circumference of circle Given that Radius of a circle is increasing at the rate of 0.7 cm/sec i.e. 𝒅𝒓/𝒅𝒕 = 0.7 cm/sec We need find rate of change of circumference of circle w. r. 𝑡 time i.e. we need to calculate 𝒅𝑪/𝒅𝒕 We know that Circumference of circle = 2πr Now, 𝑑𝐶/𝑑𝑡 = (𝑑(2𝜋𝑟))/𝑑𝑡 𝑑𝐶/𝑑𝑡 = 2π 𝒅𝒓/𝒅𝒕 𝑑𝐶/𝑑𝑡 = 2π × 0.7 𝑑𝐶/𝑑𝑡 = 1.4π (From (1): 𝑑𝑟/𝑑𝑡 = 5 ) Since circumference is in cm & time is in sec 𝑑𝐶/𝑑𝑡 = 1.4π cm/sec Hence, circumference of circle is increasing at the rate of 1.4π cm/sec

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo