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Misc 11 In how many ways can the letters of the word ASSASSINATION be arranged so that all the Sā€™s are together? Since we need to assigned 4S together, We consider 4S as one block So, our letters become We arrange them now Since letters are repeating Hence we use this formula = š‘›!/(š‘1!š‘2!š‘3! ) Here, n = Letters to be arranged = 9 + 1 = 10 Since 3A, 2I, 2N p1 = 3, p2 = 2, p3 = 2, Number of arrangements where the Sā€™s are together = 10!/3!2!2! = (10 Ɨ 9 Ɨ 8 Ɨ 7 Ɨ 6 Ɨ 5 Ɨ 4 Ɨ 3!)/(3! 2! 2!) = 151200

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo