Misc 5 - Chapter 13 Class 12 Probability
Last updated at April 16, 2024 by Teachoo
Miscellaneous
Misc 1 (ii)
Misc 2 (i) Important
Misc 2 (ii)
Misc 3
Misc 4
Misc 5 Important You are here
Misc 6
Misc 7 Important
Misc 8 Important
Misc 9 Important
Misc 10 Important
Misc 11 (MCQ) Important
Misc 12 (MCQ)
Misc 13 (MCQ)
Question 1 Important
Question 2 Important
Question 3 Important
Question 4
Question 5 Important
Question 6 Important
Last updated at April 16, 2024 by Teachoo
Misc 5 If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?A leap year has 366 days Dividing by 7, Number of weeks in a leap year = 366/7 = 52 2/7 Thus, a leap year has 52 weeks and 2 days extra. Hence, a leap year will have 52 Tuesdays for sure Now, the 2 extra days can be {(Monday, Tuesday), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat), (Sat, Sun), (Sun, Mon)} Favorable cases = Cases where we have Tuesday = {(Mon, Tues), (Tues, Wed)} Therefore, Probability that a leap year will contain 53 Tuesdays = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑜𝑣𝑜𝑟𝑎𝑏𝑙𝑒 𝑐𝑎𝑠𝑒𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑠𝑒𝑠) = 𝟐/𝟕