Question 12 - Binomial Distribution - Chapter 13 Class 12 Probability

Last updated at Dec. 16, 2024 by

Ex 13.5, 12 - Find probability of throwing at most 2 sixes in - Ex 13.5

Ex 13.5, 12 - Chapter 13 Class 12 Probability - Part 2
Ex 13.5, 12 - Chapter 13 Class 12 Probability - Part 3

Go Ad-free

Transcript

Question 12 Find the probability of throwing at most 2 sixes in 6 throws of a single die. Let X : be the number six we get on 5 throws Throwing a pair of die is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx Where n = number of times die is thrown = 6 p = Probability of getting a six = 1 6 q = 1 1 6 = 5 6 Hence, P(X = x) = 6Cx We need to find probability of throwing at most 2 sixes in 6 throws of a single die. i.e. P(X 2) P(X 2) = P(X = 0) + P(X = 1) + P(X = 2) = 6C0 1 6 0 5 6 6 +6C1 1 6 1 5 6 5 +6C2 1 6 2 5 6 4 = 1 1 5 6 6 + 6 1 6 5 6 5 + 15 1 6 2 5 6 4 = 5 6 6 + 5 6 5 + 15 1 36 5 6 4 = 5 6 6 + 5 6 5 + 5 12 5 6 4 = 5 6 4 5 6 2 + 5 6 + 5 12 = 5 6 4 25 36 + 5 6 + 5 12 = 5 6 4 25 + 30 + 15 36 = 5 6 4 70 36 = So, the required Probability is 35 18 5 6 4

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo