Ex 13.2, 11 (i) - Chapter 13 Class 12 Probability
Last updated at April 16, 2024 by Teachoo
Independent events
Ex 13.2, 1
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Chapter 13 Class 12 Probability
Concept wise
- Conditional Probability - Values given
- Conditional Probability - Statement
- Multiplication rule of probability
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Independent events
- Basic Probability
- Theorem of total probability
- Bayes theorem
- Random Variable - Defination
- Probability distribution
- Mean or Expectation of random variable
- Variance and Standard Deviation of a Random Variable
- Bernoulli Trials
- Binomial Distribution
Transcript
Ex 13.2, 11 Given two independent events A and B such that P(A) = 0.3, P(B) = 0.6. Find (i) P(A and B) Given, P(A) = 0.3 & P(B) = 0.6 Since events A & B are independent P(A ∩ B) = P(A) . P(B) Now, P(A and B) = P(A ∩ B) = P(A) . P(B) = 0.3 × 0.6 = 0.18 Ex 13.2, 11 Given two independent events A and B such that P(A) = 0.3, P(B) = 0.6. Find (i) P(A and B) Given, P(A) = 0.3 & P(B) = 0.6 Since events A & B are independent P(A ∩ B) = P(A) . P(B) Now, P(A and B) = P(A ∩ B) = P(A) . P(B) = 0.3 × 0.6 = 0.18
