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Question 1 - Finding derivative of a function by chain rule - Chapter 5 Class 12 Continuity and Differentiability
Last updated at April 16, 2024 by Teachoo
Finding derivative of a function by chain rule
Chapter 5 Class 12 Continuity and Differentiability
Concept wise
- Checking continuity at a given point
- Checking continuity at any point
- Checking continuity using LHL and RHL
- Algebra of continous functions
- Continuity of composite functions
- Checking if funciton is differentiable
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Finding derivative of a function by chain rule
- Finding derivative of Implicit functions
- Finding derivative of Inverse trigonometric functions
- Finding derivative of Exponential & logarithm functions
- Logarithmic Differentiation - Type 1
- Logarithmic Differentiation - Type 2
- Derivatives in parametric form
- Finding second order derivatives - Normal form
- Finding second order derivatives- Implicit form
- Proofs
- Verify Rolles theorem
- Verify Mean Value Theorem
Transcript
Question 1 Find the derivative of tan (2x + 3). Let y = tan (2x + 3) We need to find derivative of y, i.e. ππ¦/ππ₯ = (π tanβ‘γ(2π₯+3)γ)/ππ₯ = sec2(2x + 3) Γ (π(2π₯ + 3))/ππ₯ = sec2 (2x + 3) Γ 2 = 2 sec2 (2x + 3) (As (tan x)β = sec2 x)
